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11f^2+7f-2=0
a = 11; b = 7; c = -2;
Δ = b2-4ac
Δ = 72-4·11·(-2)
Δ = 137
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{137}}{2*11}=\frac{-7-\sqrt{137}}{22} $$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{137}}{2*11}=\frac{-7+\sqrt{137}}{22} $
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